Selenium doesnt capture colour picker

Hi,
Iam new to selenium Rc python...

In my application there is an option to choose fore colour and back ground colour using colourpickker,

This is my code for click the colour pickker
sel.click("//div[@id='collorpicker_327']/div[12]")

Even in selenium ide also doesnt capture

I have an error like this..

[error] Element //div[@id='collorpicker_327']/div[12] not found


please help me to solve the problem

try with css selector

Can you give the code using css

Provide me source code of your element which you wanted to locate using css selector so that i can try to give allocator

Dear All,

Is there any solution for this issue. I have been searching a lot for this. In my web application, we use 5 colour pickers. I need to automate them. Every time I open this page, the object ID changes for this color picker (Example : //div[@id='collorpicker_902']/div[12] in this example the number 902 to changes to some random number (444) the next time). Please provide me some steps to automate this...
Please help me!!!!

~ Harri...

Hi,
Thanks for Questioning this I have tried with this and it works for me please see is it ok for you.

sel.click("//div[6]/span/img") // This is icon which opens the color selection box "xpath".
sel.mouse_move_at("mColorPickerImg", "10,50") // mColorPickerImg is the allocator for the selection box which has
popped and the values are position where we have to click you can change as per your need
sel.click("mColorPickerImg") // click on the location where we have set the position of cursor